[Imprint][Data Privacy Statement][E-Mail]



View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 299 from proof hasSharing-put-index-refval (previous step)

st[r0 -- sks0] = refval(r1), st[r0 -- _type] .type = mkarraytype(ty), st[r4 -- sks3] = refval(r1), 0 < st[r0 -- _length] .intval, 0 ≤ i, i < st[r0 -- _length] .intval, fits(r0, sks0, st), validref(str, r4, ty, st), fits(r4, sks3, st), validref(str, r0, mkclasstype(`java.lang.Object' .class), st), validref(str, r4, mkclasstype(`java.lang.Object' .class), st), ∀ r, sks, r2, sks1. r ≠ r0 ∧ r ≠ r4 ∨ r2 ≠ r0 ∧ r2 ≠ r4 ∨ r = r2 ∨ ¬ fits(r, sks, st) ∨ ¬ fits(r2, sks1, st) ∨ st[r -- sks] ≠ st[r2 -- sks1] ∨ st[r -- sks] .refval = jvmref ⊦ sks0 = [], r1 = jvmref, r0 = r4, r0 = jvmref, sks0 = i ' ' + sks3, sks3 = [], r4 = jvmref, hasSharing(r0, st), hasSharing(r4, st), junkref(str, r0, st), ∃ sks, sks1. sks0 = sks + i ' ' + sks1 ∧ st[r0 -- sks] .refval = r0 ∧ (∀ sks2. sks2 + i ' ' ⊑ sks → st[r0 -- sks2] .refval ≠ r0), ∃ sks, sks1. sks3 = sks + i ' ' + sks1 ∧ st[r4 -- sks] .refval = r0 ∧ (∀ sks2. sks2 + i ' ' ⊑ sks → st[r4 -- sks2] .refval ≠ st[r4 -- sks] .refval)

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 12, [extquanttermlist: (r0, sks0, r4, sks3) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r])], [EXTRATERMS : (r0, sks0, r4, sks3)]]