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Proof step 428 from proof hasSharing-put-index-refval (previous step)

st[r3 -- sks0] = refval(r0), st[r0 -- _type] .type = mkarraytype(ty), st[r3 -- sks2] = refval(r1), st[r -- sks1] = refval(r0), (st[r0 -- i ', refval(r3)][r3 -- (sks0 + i ' ' + sks)]) = refval(r1), st[r3 -- sks3] = refval(r0), 0 < st[r0 -- _length] .intval, fits(r, sks1, st), disjoint(str, r ' + r3 ', st), validref(str, r3, ty, st), is_referencevalue(st[r0 -- i ', refval(r3)][r0 -- (i ' ' + sks2)]), fits(r3, sks2, st), is_referencevalue(st[r0 -- i ', refval(r3)][r0 -- (i ' ' + sks0 + i ' ' + sks)]), 0 ≤ i, i < st[r0 -- _length] .intval, fits(r3, sks0 + i ' ' + sks, st), sks3 + i ' ' ⊑ sks0, ∀ sks. sks + i ' ' ⊑ sks0 → st[r3 -- sks] .refval ≠ r0 ⊦ sks1 = [], r0 = jvmref, r = r3, r1 = jvmref, sks2 = sks0 + i ' ' + sks, r3 = jvmref, junkref(str, r, st), hasSharing(r3, st), hasSharing(r, st), ∃ sks, sks4. sks1 = sks + i ' ' + sks4 ∧ st[r -- sks] .refval = r0 ∧ (∀ sks5. sks5 + i ' ' ⊑ sks → st[r -- sks5] .refval ≠ st[r -- sks] .refval), ∃ sks4. ¬ (sks4 + i ' ' ⊑ sks1 → st[r -- sks4] .refval ≠ r0), ∃ sks, sks2. sks1 = sks + i ' ' + sks2 ∧ st[r -- sks] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks → st[r -- sks4] .refval ≠ st[r -- sks] .refval), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ r0), ∃ sks, sks1. sks2 = sks + i ' ' + sks1 ∧ st[r3 -- sks] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks → st[r3 -- sks4] .refval ≠ st[r3 -- sks] .refval)

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 18, [extquanttermlist: (sks3)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r])], [EXTRATERMS : (sks3)]]