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Proof step 466 from proof hasSharing-put-index-refval (previous step)

(st[r0 -- i ', refval(r4)][r -- sks]) = refval(r2) ∧ is_referencevalue(st[r0 -- i ', refval(r4)][r -- sks]), st[r -- sks] = refval(r0), st[r -- sks1] = refval(r0), (st[r0 -- i ', refval(r4)][r4 -- sks3]) = refval(r1), st[r0 -- _type] .type = mkarraytype(ty), (st[r0 -- i ', refval(r4)][r -- (sks + i ' ' + sks2)]) = refval(r1), 0 ≤ i, i < st[r0 -- _length] .intval, fits(r4, sks3, st[r0 -- i ', refval(r4)]), fits(r, sks1, st), disjoint(str, r ' + r4 ', st), validref(str, r4, ty, st), fits(r2, i ' ' + sks2, st[r0 -- i ', refval(r4)]), fits(r, sks, st[r0 -- i ', refval(r4)]), is_referencevalue(st[r0 -- i ', refval(r4)][r0 -- (i ' ' + sks3)]), 0 < st[r0 -- _length] .intval, r4 = jvmref → is_reftype(ty) ⊦ r0 = jvmref, r = r4, r1 = jvmref, sks + i ' ' + sks2 = sks1 + i ' ' + sks3, sks1 = [], junkref(str, r, st), hasSharing(r4, st), hasSharing(r, st), ∃ sks4. ¬ (sks4 + i ' ' ⊑ sks → st[r -- sks4] .refval ≠ r0), ∃ sks0, sks2. sks1 = sks0 + i ' ' + sks2 ∧ st[r -- sks0] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks0 → st[r -- sks4] .refval ≠ st[r -- sks0] .refval), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ r0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 465:
(st[r0 -- i ', refval(r4)][r -- (sks + i ' ' + sks2)]) = refval(r1), st[r0 -- _type] .type = mkarraytype(ty), (st[r0 -- i ', refval(r4)][r4 -- sks3]) = refval(r1), st[r -- sks1] = refval(r0), st[r -- sks] = refval(r0), (st[r0 -- i ', refval(r4)][r -- sks]) = refval(r2), 0 < st[r0 -- _length] .intval, is_referencevalue(st[r0 -- i ', refval(r4)][r0 -- (i ' ' + sks3)]), fits(r, sks, st[r0 -- i ', refval(r4)]), fits(r2, i ' ' + sks2, st[r0 -- i ', refval(r4)]), validref(str, r4, ty, st), disjoint(str, r ' + r4 ', st), fits(r, sks1, st), fits(r4, sks3, st[r0 -- i ', refval(r4)]), i < st[r0 -- _length] .intval, 0 ≤ i, r4 = jvmref → is_reftype(ty) ⊦ sks1 = [], sks + i ' ' + sks2 = sks1 + i ' ' + sks3, r1 = jvmref, r = r4, r0 = jvmref, hasSharing(r, st), hasSharing(r4, st), junkref(str, r, st), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ r0), ∃ sks0, sks2. sks1 = sks0 + i ' ' + sks2 ∧ st[r -- sks0] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks0 → st[r -- sks4] .refval ≠ st[r -- sks0] .refval), ∃ sks4. ¬ (sks4 + i ' ' ⊑ sks → st[r -- sks4] .refval ≠ r0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , test-19, ⊦ is_referencevalue(refval(r))])]]