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Proof step 520 from proof hasSharing-put-index-refval (previous step)

st[r -- sks0] = refval(r1), st[r0 -- _type] .type = mkarraytype(ty), (st[r0 -- i ', refval(r4)][r4 -- (sks + i ' ' + sks4)]) = refval(r1), st[r -- sks1] = refval(r0), st[r4 -- sks] = refval(r0), 0 < st[r0 -- _length] .intval, is_referencevalue(st[r0 -- i ', refval(r4)][r0 -- (i ' ' + sks + i ' ' + sks4)]), fits(r, sks0, st), validref(str, r4, ty, st), disjoint(str, r ' + r4 ', st), fits(r, sks1, st), fits(r4, sks, st[r0 -- i ', refval(r4)]) ∧ fits((st[r0 -- i ', refval(r4)][r4 -- sks]) .refval, i ' ' + sks4, st[r0 -- i ', refval(r4)]), i < st[r0 -- _length] .intval, 0 ≤ i ⊦ r4 = jvmref, sks1 = [], sks0 = sks1 + i ' ' + sks + i ' ' + sks4, sks0 = [], r1 = jvmref, r = r4, r0 = jvmref, hasSharing(r, st), hasSharing(r4, st), junkref(str, r, st), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ r0), ∃ sks0, sks2. sks1 = sks0 + i ' ' + sks2 ∧ st[r -- sks0] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks0 → st[r -- sks4] .refval ≠ st[r -- sks0] .refval), ∃ sks1, sks2. sks0 = sks1 + i ' ' + sks2 ∧ st[r -- sks1] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks1 → st[r -- sks4] .refval ≠ st[r -- sks1] .refval), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks → st[r4 -- sks2] .refval ≠ r0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 519:
st[r4 -- sks] = refval(r0), st[r -- sks1] = refval(r0), (st[r0 -- i ', refval(r4)][r4 -- (sks + i ' ' + sks4)]) = refval(r1), st[r0 -- _type] .type = mkarraytype(ty), st[r -- sks0] = refval(r1), 0 ≤ i, i < st[r0 -- _length] .intval, fits((st[r0 -- i ', refval(r4)][r4 -- sks]) .refval, i ' ' + sks4, st[r0 -- i ', refval(r4)]), fits(r4, sks, st[r0 -- i ', refval(r4)]), fits(r, sks1, st), disjoint(str, r ' + r4 ', st), validref(str, r4, ty, st), fits(r, sks0, st), is_referencevalue(st[r0 -- i ', refval(r4)][r0 -- (i ' ' + sks + i ' ' + sks4)]), 0 < st[r0 -- _length] .intval ⊦ r0 = jvmref, r = r4, r1 = jvmref, sks0 = [], sks0 = sks1 + i ' ' + sks + i ' ' + sks4, sks1 = [], r4 = jvmref, junkref(str, r, st), hasSharing(r4, st), hasSharing(r, st), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks → st[r4 -- sks2] .refval ≠ r0), ∃ sks1, sks2. sks0 = sks1 + i ' ' + sks2 ∧ st[r -- sks1] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks1 → st[r -- sks4] .refval ≠ st[r -- sks1] .refval), ∃ sks0, sks2. sks1 = sks0 + i ' ' + sks2 ∧ st[r -- sks0] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks0 → st[r -- sks4] .refval ≠ st[r -- sks0] .refval), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ r0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]