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Proof step 62 from proof hasSharing-put-index-refval (previous step)

(st[r -- i ', refval(r2)][r2 -- (sks0 + i ' ' + sks)]) = refval(r2), st[r -- _type] .type = mkarraytype(ty), st[r2 -- sks0] = refval(r), 0 < st[r -- _length] .intval, fits(r2, sks0 + i ' ' + sks, st), validref(str, r2, ty, st), disjoint(str, r ' + r2 ', st), 0 ≤ i, i < st[r -- _length] .intval, ∀ sks1. sks1 + i ' ' ⊑ sks0 → st[r2 -- sks1] .refval ≠ r ⊦ r2 = jvmref, r = r2, r = jvmref, hasSharing(r, st), hasSharing(r2, st), junkref(str, r, st), ∃ sks1, sks2. sks0 + i ' ' + sks = sks1 + i ' ' + sks2 ∧ st[r2 -- sks1] .refval = r ∧ (∀ sks3. sks3 + i ' ' ⊑ sks1 → st[r2 -- sks3] .refval ≠ st[r2 -- sks1] .refval)

User applied rule exists right

And obtained the following new goals

Proof step 61:
(st[r -- i ', refval(r2)][r2 -- (sks0 + i ' ' + sks)]) = refval(r2), st[r -- _type] .type = mkarraytype(ty), st[r2 -- sks0] = refval(r), 0 < st[r -- _length] .intval, fits(r2, sks0 + i ' ' + sks, st), validref(str, r2, ty, st), disjoint(str, r ' + r2 ', st), 0 ≤ i, i < st[r -- _length] .intval, ∀ sks1. sks1 + i ' ' ⊑ sks0 → st[r2 -- sks1] .refval ≠ r ⊦ r2 = jvmref, r = r2, r = jvmref, hasSharing(r, st), hasSharing(r2, st), junkref(str, r, st), sks0 + i ' ' + sks = sks0 + i ' ' + sks ∧ st[r2 -- sks0] .refval = r ∧ (∀ sks3. sks3 + i ' ' ⊑ sks0 → st[r2 -- sks3] .refval ≠ st[r2 -- sks0] .refval)

Rule argument

[EXRARG : pos: right 7, [extquanttermlist: (sks0, sks) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sks0, sks)]]