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Proof step 630 from proof hasSharing-put-index-refval (previous step)

st[r1 -- sks0] = refval(r), st[r -- sks] = refval(r1), st[r -- _type] .type = mkarraytype(ty), fits(r1, sks0 + i ' ', st[r -- i ', refval(r1)]), fits(r, sks, st), validref(str, r1, ty, st), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval, validref(str, r, mkclasstype(`java.lang.Object' .class), st), validref(str, r1, mkclasstype(`java.lang.Object' .class), st), ∀ r0, sks1, r2, sks2. r0 ≠ r ∧ r0 ≠ r1 ∨ r2 ≠ r ∧ r2 ≠ r1 ∨ r0 = r2 ∨ ¬ fits(r0, sks1, st) ∨ ¬ fits(r2, sks2, st) ∨ st[r0 -- sks1] ≠ st[r2 -- sks2] ∨ st[r0 -- sks1] .refval = jvmref ⊦ i ' ' + sks0 + i ' ' = sks, r = jvmref, r = r1, sks = [], r1 = jvmref, sks0 = [], junkref(str, r, st), hasSharing(r1, st), hasSharing(r, st), ∃ sks1, sks3. sks = sks1 + i ' ' + sks3 ∧ st[r -- sks1] .refval = r ∧ (∀ sks2. sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ st[r -- sks1] .refval), ∃ sks3. ¬ (sks3 + i ' ' ⊑ sks0 → st[r1 -- sks3] .refval ≠ r), ∃ sks2, sks4. sks0 = sks2 + i ' ' + sks4 ∧ st[r1 -- sks2] .refval = r ∧ (∀ sks3. sks3 + i ' ' ⊑ sks2 → st[r1 -- sks3] .refval ≠ st[r1 -- sks2] .refval)

User applied rule all left

And obtained the following new goals

Rule argument

[EXRARG : pos: left 12, [extquanttermlist: (r, sks, r1, []) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : storefuns, , lookup-empty, ⊦ st[r -- []] = refval(r)], [CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r])], [EXTRATERMS : (r, sks, r1, [])]]