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Proof step 638 from proof hasSharing-put-index-refval (previous step)

st[r2 -- sks2] = refval(r) ∧ is_referencevalue(st[r2 -- sks2]), (st[r -- i ', refval(r2)][r2 -- (sks2 + i ' ' + sks4)]) = refval(r0), (st[r -- i ', refval(r2)][r2 -- sks1]) = refval(r1), st[r2 -- (sks2 + i ' ' + sks4)] = refval(r), st[r -- sks] = refval(r1), st[r -- _type] .type = mkarraytype(ty), fits(r0, i ' ' + sks1, st[r -- i ', refval(r2)]), fits(r2, sks2 + i ' ' + sks4, st[r -- i ', refval(r2)]), fits(r, sks, st), disjoint(str, r ' + r2 ', st), validref(str, r2, ty, st), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval ⊦ sks1 = [], i ' ' + (sks2 + i ' ' + sks4) + i ' ' + sks1 = sks, r = jvmref, r = r2, r1 = jvmref, sks = [], r2 = jvmref, junkref(str, r, st), hasSharing(r2, st), hasSharing(r, st), ∃ sks3. ¬ (sks3 + i ' ' ⊑ sks2 → st[r2 -- sks3] .refval ≠ r), ∃ sks1, sks3. sks = sks1 + i ' ' + sks3 ∧ st[r -- sks1] .refval = r ∧ (∀ sks0. sks0 + i ' ' ⊑ sks1 → st[r -- sks0] .refval ≠ st[r -- sks1] .refval), ∃ sks3. ¬ (sks3 + i ' ' ⊑ sks2 + i ' ' + sks4 → st[r2 -- sks3] .refval ≠ r), ∃ sks, sks1. sks2 + i ' ' + sks4 = sks + i ' ' + sks1 ∧ st[r2 -- sks] .refval = r ∧ (∀ sks3. sks3 + i ' ' ⊑ sks → st[r2 -- sks3] .refval ≠ st[r2 -- sks] .refval)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 637:
st[r -- _type] .type = mkarraytype(ty), st[r -- sks] = refval(r1), st[r2 -- (sks2 + i ' ' + sks4)] = refval(r), (st[r -- i ', refval(r2)][r2 -- sks1]) = refval(r1), (st[r -- i ', refval(r2)][r2 -- (sks2 + i ' ' + sks4)]) = refval(r0), st[r2 -- sks2] = refval(r), 0 < st[r -- _length] .intval, 0 ≤ i, i < st[r -- _length] .intval, validref(str, r2, ty, st), disjoint(str, r ' + r2 ', st), fits(r, sks, st), fits(r2, sks2 + i ' ' + sks4, st[r -- i ', refval(r2)]), fits(r0, i ' ' + sks1, st[r -- i ', refval(r2)]) ⊦ r2 = jvmref, sks = [], r1 = jvmref, r = r2, r = jvmref, i ' ' + (sks2 + i ' ' + sks4) + i ' ' + sks1 = sks, sks1 = [], hasSharing(r, st), hasSharing(r2, st), junkref(str, r, st), ∃ sks, sks1. sks2 + i ' ' + sks4 = sks + i ' ' + sks1 ∧ st[r2 -- sks] .refval = r ∧ (∀ sks3. sks3 + i ' ' ⊑ sks → st[r2 -- sks3] .refval ≠ st[r2 -- sks] .refval), ∃ sks3. ¬ (sks3 + i ' ' ⊑ sks2 + i ' ' + sks4 → st[r2 -- sks3] .refval ≠ r), ∃ sks1, sks3. sks = sks1 + i ' ' + sks3 ∧ st[r -- sks1] .refval = r ∧ (∀ sks0. sks0 + i ' ' ⊑ sks1 → st[r -- sks0] .refval ≠ st[r -- sks1] .refval), ∃ sks3. ¬ (sks3 + i ' ' ⊑ sks2 → st[r2 -- sks3] .refval ≠ r)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , test-19, ⊦ is_referencevalue(refval(r))], [CSIMPNAMEDFORWARD : int-abs, , forward-le-05, ⊦ i < j ∧ 0 ≤ i → 0 < j])]]