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Proof step 659 from proof hasSharing-put-index-refval (previous step)

sks0 ≠ [] ∧ i ' ' + sks1 ≠ [], st[r -- sks] = refval(r1), st[r -- _type] .type = mkarraytype(ty), (st[r -- i ', refval(r2)][(st[r -- i ', refval(r2)][r2 -- sks0]) .refval -- (i ' ' + sks1)]) = refval(r1), st[r2 -- sks0] = refval(r), 0 < st[r -- _length] .intval, fits(r2, sks0 + i ' ' + sks1, st[r -- i ', refval(r2)]), fits(r, sks, st), disjoint(str, r ' + r2 ', st), validref(str, r2, ty, st), i < st[r -- _length] .intval, 0 ≤ i ⊦ i ' ' + sks0 + i ' ' + sks1 = sks, r = jvmref, r = r2, r1 = jvmref, sks = [], r2 = jvmref, junkref(str, r, st), hasSharing(r2, st), hasSharing(r, st), ∃ sks1, sks3. sks = sks1 + i ' ' + sks3 ∧ st[r -- sks1] .refval = r ∧ (∀ sks2. sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ st[r -- sks1] .refval), ∃ sks3. ¬ (sks3 + i ' ' ⊑ sks0 → st[r2 -- sks3] .refval ≠ r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 658:
st[r -- sks] = refval(r1), st[r -- _type] .type = mkarraytype(ty), (st[r -- i ', refval(r2)][(st[r -- i ', refval(r2)][r2 -- sks0]) .refval -- (i ' ' + sks1)]) = refval(r1), st[r2 -- sks0] = refval(r), 0 < st[r -- _length] .intval, fits(r2, sks0 + i ' ' + sks1, st[r -- i ', refval(r2)]), fits(r, sks, st), disjoint(str, r ' + r2 ', st), validref(str, r2, ty, st), i < st[r -- _length] .intval, 0 ≤ i ⊦ i ' ' + sks0 + i ' ' + sks1 = sks, r = jvmref, r = r2, r1 = jvmref, sks = [], r2 = jvmref, sks0 = [], junkref(str, r, st), hasSharing(r2, st), hasSharing(r, st), ∃ sks1, sks3. sks = sks1 + i ' ' + sks3 ∧ st[r -- sks1] .refval = r ∧ (∀ sks2. sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ st[r -- sks1] .refval), ∃ sks3. ¬ (sks3 + i ' ' ⊑ sks0 → st[r2 -- sks3] .refval ≠ r)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : list, storekeys, e-01, ⊦ sk ' + sks ≠ []])]]