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Proof step 712 from proof hasSharing-put-index-refval (previous step)

st[r0 -- _type] .type = mkarraytype(ty), st[r -- sks] = refval(r1), st[r -- sks1] = refval(r0), (st[r0 -- i ', refval(r2)][r2 -- ((sks2 + i ' ' + sks4) + i ' ' + sks3)]) = refval(r1), st[r2 -- (sks2 + i ' ' + sks4)] = refval(r0), (st[r0 -- i ', refval(r2)][r2 -- (sks2 + i ' ' + sks4)]) = refval(r3), st[r2 -- sks2] = refval(r0), 0 < st[r0 -- _length] .intval, 0 ≤ i, i < st[r0 -- _length] .intval, validref(str, r2, ty, st), disjoint(str, r ' + r2 ', st), fits(r, sks, st), fits(r, sks1, st), fits(r2, sks2 + i ' ' + sks4, st[r0 -- i ', refval(r2)]), fits(r3, i ' ' + sks3, st[r0 -- i ', refval(r2)]) ⊦ sks1 = [], sks1 + i ' ' + (sks2 + i ' ' + sks4) + i ' ' + sks3 = sks, sks = [], r1 = jvmref, r = r2, r0 = jvmref, r2 = jvmref, hasSharing(r, st), hasSharing(r2, st), junkref(str, r, st), ∃ sks1, sks3. sks = sks1 + i ' ' + sks3 ∧ st[r -- sks1] .refval = r0 ∧ (∀ sks2. sks2 + i ' ' ⊑ sks1 → st[r -- sks2] .refval ≠ st[r -- sks1] .refval), ∃ sks3. ¬ (sks3 + i ' ' ⊑ sks1 → st[r -- sks3] .refval ≠ r0), ∃ sks, sks3. sks1 = sks + i ' ' + sks3 ∧ st[r -- sks] .refval = r0 ∧ (∀ sks4. sks4 + i ' ' ⊑ sks → st[r -- sks4] .refval ≠ st[r -- sks] .refval), ∃ sks. ¬ (sks + i ' ' ⊑ sks2 + i ' ' + sks4 → st[r2 -- sks] .refval ≠ r0), ∃ sks5. ¬ (sks5 + i ' ' ⊑ sks2 → st[r2 -- sks5] .refval ≠ r0)

User applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 14, [extquanttermlist: (sks2)abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list-last, storekeys, app-01-02, ⊦ sks + sks0 ⊑ sks + sks1 ↔ sks0 ⊑ sks1], [CSIMPNAMEDSEQ : list-last, storekeys, prefix-one, ⊦ sk ' ⊑ sk0 ' + sks ↔ sk = sk0], [CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r])], [EXTRATERMS : (sks2)]]