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Proof step 28 from proof hasSharing-put-statfield (previous step)

∀ st, sk, val, sks, r0. (st[jvmref -- sk, val][jvmref -- sks]) = refval(r0) ∧ (st[jvmref -- sk, val][jvmref -- sks1]) = refval(r0) ∧ fits(jvmref, sks1, st) ∧ fits(jvmref, sks, st) ∧ (st[jvmref -- sks] .refval = jvmref ∨ st[jvmref -- sks] ≠ st[jvmref -- sks1]) → sks1 = sks ∨ sks1 = [] ∨ sks = [] ∨ r0 = jvmref, (st[jvmref -- sk, val][jvmref -- sks]) = refval(r0), (st[jvmref -- sk, val][jvmref -- (sk0 + sks1)]) = refval(r0), fits(jvmref, sk0 + sks1, st), fits(jvmref, sks, st), st[jvmref -- sks] .refval = jvmref ∨ st[jvmref -- sks] ≠ st[jvmref -- (sk0 + sks1)] ⊦ sk0 + sks1 = sks, sk0 + sks1 = [], sks = [], r0 = jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
(st[jvmref -- sk, val][jvmref -- sks]) = refval(r0), (st[jvmref -- sk, val][jvmref -- (sk0 ' + sks1)]) = refval(r0), fits(jvmref, sks, st), fits(jvmref, sk0 ' + sks1, st), ∀ st, sk, val, sks, r0. (st[jvmref -- sk, val][jvmref -- sks]) = refval(r0) ∧ (st[jvmref -- sk, val][jvmref -- sks1]) = refval(r0) ∧ fits(jvmref, sks1, st) ∧ fits(jvmref, sks, st) ∧ (st[jvmref -- sks] .refval = jvmref ∨ st[jvmref -- sks] ≠ st[jvmref -- sks1]) → sks1 = sks ∨ sks1 = [] ∨ sks = [] ∨ r0 = jvmref, st[jvmref -- sks] .refval = jvmref ∨ st[jvmref -- sks] ≠ st[jvmref -- (sk0 ' + sks1)] ⊦ sks = [], r0 = jvmref, sk0 ' + sks1 = sks

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPSEQ : ⊦ sk ' + sks ≠ []], [CSIMPSEQ : ⊦ sk + sks = sk ' + sks])]]