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Proof step 45 from proof hasSharing-put-statfield (previous step)

⊦ ¬ (∃ sks1, sks2. fits(r, sks1, st[jvmref -- sk, val]) ∧ fits(r, sks2, st[jvmref -- sk, val]) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ (st[jvmref -- sk, val][r -- sks1]) .refval ≠ jvmref ∧ (st[jvmref -- sk, val][r -- sks1]) = (st[jvmref -- sk, val][r -- sks2])) ↔ ¬ hasSharing(r, st), junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 44:
⊦ (∀ sks, sks0. ¬ fits(r, sks, st[jvmref -- sk, val]) ∨ ¬ fits(r, sks0, st[jvmref -- sk, val]) ∨ sks = sks0 ∨ sks = [] ∨ sks0 = [] ∨ (st[jvmref -- sk, val][r -- sks]) .refval = jvmref ∨ (st[jvmref -- sk, val][r -- sks]) ≠ (st[jvmref -- sk, val][r -- sks0])) ↔ ¬ hasSharing(r, st), junkref(str, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]