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Proof step 39 from proof hasSharing-putbar (previous step)

okbytearray(r0, st), ∃ sks1, sks2. fits(r, sks1, putByteArray(bytes, r0, i, st)) ∧ fits(r, sks2, putByteArray(bytes, r0, i, st)) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ (putByteArray(bytes, r0, i, st)[r -- sks1]) .refval ≠ jvmref ∧ (putByteArray(bytes, r0, i, st)[r -- sks1]) = (putByteArray(bytes, r0, i, st)[r -- sks2]) ⊦ junkref(str, r, st), ∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
(putByteArray(bytes, r0, i, st)[r -- sks0]) = (putByteArray(bytes, r0, i, st)[r -- sks]), okbytearray(r0, st), fits(r, sks0, putByteArray(bytes, r0, i, st)), fits(r, sks, putByteArray(bytes, r0, i, st)) ⊦ (putByteArray(bytes, r0, i, st)[r -- sks]) .refval = jvmref, sks = [], sks0 = [], sks0 = sks, junkref(str, r, st), ∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]