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Proof step 17 from proof hasSharing-rec (previous step)

⊦ hasSharing(r ' + refs, st) ↔ hasSharing(r, st) ∨ hasSharing(refs, st)

User applied rule case distinction

And obtained the following new goals

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]