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Proof step 15 from proof hasSharing-subset (previous step)

st[r -- sks] = refval(r0), st1[r -- sks0] = refval(r0), st ⊆ st1, fits(r, sks0, st1), fits(r, sks, st1), r -- sks ∈ st ⊦ sks = [], r0 = jvmref, sks0 = [], sks0 = sks, refval(r0) = st[r -- sks0], junkref(str, r, st), r -- sks0 ∈ st, fits(r, sks0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ ¬ junkref(str, r, st0) ∧ fits(r, sks, st) ∧ st0 ⊆ st → fits(r, sks, st0)

Rule argument

[crewrite-arg: fits-subset , F , [str, r, st0, sks, st] → [str, r, st, sks0, st1] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str, r, st, sks0, st1)]]