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Proof step 107 from proof hassharing-validrefs-dups (previous step)

refs = r + refs0 ∧ refs ≠ [], validrefs(str, refs, st[r -- _type] .type, st), dups(refs) ⊦ hasSharing(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 106:
validrefs(str, r ' + refs0, st[r -- _type] .type, st) ⊦ hasSharing(r, st), ¬ r ∈ refs0 ∧ ¬ dups(refs0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ dups(r ' + refs) ↔ ¬ ¬ (r ∈ refs ∨ dups(refs))], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]