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Proof step 44 from proof hassharing-validrefs-dups (previous step)

st[r1 -- sks0] = refval(r2), st[r -- i '] = refval(r1), st[r1 -- sks] = refval(r2), 0 < st[r -- _length] .intval, 0 ≤ i, validrefs(str, r1 ' + refs1, st[r -- _type] .type .type, st), i < st[r -- _length] .intval, is_array(str, r, st), validrefs(str, r1 ' + refs1, st[r1 -- _type] .type, st), fits(r1, sks, st), fits(r1, sks0, st), ∀ st0, str, refs, r0. # (r0 ' + refs) < # (r ' + (r1 + refs1)) → (validrefs(str, r0 ' + refs, st0[r0 -- _type] .type, st0) → hasSharing(r0, st0) ∨ ¬ r0 ∈ refs ∧ ¬ dups(refs)) ⊦ sks0 = sks, sks0 = [], sks = [], r2 = jvmref, r = jvmref, r ∈ refs1, is_classtype(st[r -- _type] .type), ¬ r1 ∈ refs1 ∧ ¬ dups(refs1), st[r -- (i ' ' + sks)] = st[r -- (i ' ' + sks0)] ∧ st[r -- (i ' ' + sks)] .refval ≠ jvmref

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,sks ≠ [] → st[r -- (sk ' + sks)] = st[st[r -- sk] .refval -- sks] ,[sks, sk, r, st] → [sks, i ', r, st] ,F ,storefuns , ,lookup-rec-01 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sks, i ', r, st)]]