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Proof step 33 from proof put-switch-primval-field-field (previous step)

¬ (¬ mkfs(class0, ty0, fieldvar0) ' ∈ sks1 ∧ sks1 ≠ []), st[r0 -- sks] = refval(r2), st[r -- sks1] = refval(r1), fits(r, sks1 + mkfs(class, ty, fieldvar) ' ', st), fits(r0, sks + mkfs(class0, ty0, fieldvar0) ' ', st), r1 ≠ r2 ∨ class ≠ class0 ∨ ty ≠ ty0 ∨ fieldvar ≠ fieldvar0 ⊦ sks1 = [], sks = [], (st[r1 -- mkfs(class, ty, fieldvar) ', val][r2 -- mkfs(class0, ty0, fieldvar0) ', val0]) = (st[r2 -- mkfs(class0, ty0, fieldvar0) ', val0] [(st[r2 -- mkfs(class0, ty0, fieldvar0) ', val0][r -- sks1]) .refval -- mkfs(class, ty, fieldvar) ', val ] ), mkfs(class, ty, fieldvar) ' ∈ sks, junkref(str, r0, st), junkref(str, r, st), is_reftype(ty0), is_reftype(ty), is_referencevalue(val0), is_referencevalue(val)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
st[r0 -- sks] = refval(r2), st[r -- sks1] = refval(r1), fits(r, sks1 + mkfs(class, ty, fieldvar) ' ', st), fits(r0, sks + mkfs(class0, ty0, fieldvar0) ' ', st), mkfs(class0, ty0, fieldvar0) ' ∈ sks1, r1 ≠ r2 ∨ class ≠ class0 ∨ ty ≠ ty0 ∨ fieldvar ≠ fieldvar0 ⊦ sks1 = [], sks = [], (st[r1 -- mkfs(class, ty, fieldvar) ', val][r2 -- mkfs(class0, ty0, fieldvar0) ', val0]) = (st[r2 -- mkfs(class0, ty0, fieldvar0) ', val0] [(st[r2 -- mkfs(class0, ty0, fieldvar0) ', val0][r -- sks1]) .refval -- mkfs(class, ty, fieldvar) ', val ] ), mkfs(class, ty, fieldvar) ' ∈ sks, junkref(str, r0, st), junkref(str, r, st), is_reftype(ty0), is_reftype(ty), is_referencevalue(val0), is_referencevalue(val)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]