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Proof step 39 from proof put-switch-primval-field-index (previous step)

¬ (¬ i ' ∈ sks1 ∧ sks1 ≠ []), st[r0 -- sks] = refval(r2), st[r -- sks1] = refval(r1), fits(r0, sks + i ' ', st), fits(r, sks1 + mkfs(class, ty, fieldvar) ' ', st) ⊦ sks = [], (st[r2 -- i ', val0][r1 -- mkfs(class, ty, fieldvar) ', val]) = (st[r2 -- i ', val0][(st[r2 -- i ', val0][r -- sks1]) .refval -- mkfs(class, ty, fieldvar) ', val]), mkfs(class, ty, fieldvar) ' ∈ sks, is_referencevalue(val), is_referencevalue(val0), is_reftype(ty), is_referencevalue(st[r0 -- (sks + i ' ')]), junkref(str, r, st), junkref(str, r0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
st[r -- sks1] = refval(r1), st[r0 -- sks] = refval(r2), fits(r, sks1 + mkfs(class, ty, fieldvar) ' ', st), fits(r0, sks + i ' ', st) ⊦ (st[r2 -- i ', val0][r1 -- mkfs(class, ty, fieldvar) ', val]) = (st[r2 -- i ', val0][(st[r2 -- i ', val0][r -- sks1]) .refval -- mkfs(class, ty, fieldvar) ', val]), sks = [], junkref(str, r0, st), junkref(str, r, st), is_referencevalue(st[r0 -- (sks + i ' ')]), is_reftype(ty), is_referencevalue(val0), is_referencevalue(val), mkfs(class, ty, fieldvar) ' ∈ sks, ¬ i ' ∈ sks1 ∧ sks1 ≠ []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]