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Proof step 16 from proof put-switch-primval-index-index (previous step)

¬ ( ¬ is_referencevalue(st[r2 -- sk0]) ∧ fits(r, sks1, st) ∧ ¬ junkref(str, r2, st) ∧ ¬ junkref(str, r, st) ∧ is_referencevalue(st[r -- sks1]) ∧ sks1 ≠ []), st[r -- sks1] = refval(r1), fits(r2, sk0 ', st), fits(r, sks1 + sk ', st), is_indexkey(sk0), is_indexkey(sk), r1 ≠ r2 ∨ sk ≠ sk0, r2 ≠ r1 ∨ sk0 ≠ sk ⊦ (st[r2 -- sk0, val0][r1 -- sk, val]) = (st[r2 -- sk0, val0][(st[r2 -- sk0, val0][r -- sks1]) .refval -- sk, val]), is_referencevalue(st[r2 -- sk0]), junkref(str, r, st), junkref(str, r2, st), is_referencevalue(val), is_referencevalue(val0), is_referencevalue(st[r -- (sks1 + sk ')])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ ¬ is_referencevalue(st[r -- sks]) ∧ ¬ junkref(str, r, st) → ¬ fits(r, sks + sk ', st)
Proof step 15:
st[r -- sks1] = refval(r1), is_indexkey(sk), is_indexkey(sk0), fits(r, sks1 + sk ', st), fits(r2, sk0 ', st), r2 ≠ r1 ∨ sk0 ≠ sk, r1 ≠ r2 ∨ sk ≠ sk0 ⊦ (st[r2 -- sk0, val0][r1 -- sk, val]) = (st[r2 -- sk0, val0][(st[r2 -- sk0, val0][r -- sks1]) .refval -- sk, val]), is_referencevalue(st[r -- (sks1 + sk ')]), is_referencevalue(val0), is_referencevalue(val), junkref(str, r2, st), junkref(str, r, st), is_referencevalue(st[r2 -- sk0]), sks1 ≠ [] ∧ fits(r, sks1, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , test-19, ⊦ is_referencevalue(refval(r))], [CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1])]]