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Proof step 35 from proof put-switch-primval-index-index (previous step)

st[r0 -- sks] = refval(r2), st[r -- sks1] = refval(r1), fits(r, sks1, st), fits(r0, sks, st), fits(r2, sk0 ', st), is_indexkey(sk), ∃ i. sk0 = i ', fits(r1, sk ', st), r1 ≠ r2 ∨ sk ≠ sk0 ⊦ sks = [], (st[r1 -- sk, val][(st[r1 -- sk, val][r0 -- sks]) .refval -- sk0, val0]) = (st[r2 -- sk0, val0][(st[r2 -- sk0, val0][r -- sks1]) .refval -- sk, val]), junkref(str, r0, st), junkref(str, r, st), is_referencevalue(st[r0 -- (sks + sk0 ')]), is_referencevalue(st[r -- (sks1 + sk ')]), is_referencevalue(val0), is_referencevalue(val), ¬ junkref(str, r1, st) ∧ ¬ is_referencevalue(st[r1 -- sk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
st[r0 -- sks] = refval(r2), st[r -- sks1] = refval(r1), fits(r, sks1, st), fits(r0, sks, st), fits(r2, i ' ', st), is_indexkey(sk), fits(r1, sk ', st), r1 ≠ r2 ∨ sk ≠ i ' ⊦ sks = [], (st[r1 -- sk, val][(st[r1 -- sk, val][r0 -- sks]) .refval -- i ', val0]) = (st[r2 -- i ', val0][(st[r2 -- i ', val0][r -- sks1]) .refval -- sk, val]), junkref(str, r0, st), junkref(str, r, st), is_referencevalue(st[r0 -- (sks + i ' ')]), is_referencevalue(st[r -- (sks1 + sk ')]), is_referencevalue(val0), is_referencevalue(val), ¬ junkref(str, r1, st) ∧ ¬ is_referencevalue(st[r1 -- sk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]