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Proof step 62 from proof put-switch-primval-index-index (previous step)

r2 -- sk0 ≠ r1 -- sk, st[r0 -- sks] = refval(r2), st[r -- sks1] = refval(r1), is_indexkey(sk), is_indexkey(sk0), fits(r, sks1 + sk ', st), fits(r0, sks + sk0 ', st), fits(r0, sks, st), r1 ≠ r2 ∨ sk ≠ sk0 ⊦ sks = [], (st[r2 -- sk0, val0][r1 -- sk, val]) = (st[r2 -- sk0, val0][(st[r2 -- sk0, val0][r -- sks1]) .refval -- sk, val]), is_referencevalue(st[r1 -- sk]), junkref(str, r1, st), junkref(str, r0, st), junkref(str, r, st), is_referencevalue(st[r0 -- (sks + sk0 ')]), is_referencevalue(st[r -- (sks1 + sk ')]), is_referencevalue(val0), is_referencevalue(val)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 61:
st[r0 -- sks] = refval(r2), st[r -- sks1] = refval(r1), is_indexkey(sk), is_indexkey(sk0), fits(r, sks1 + sk ', st), fits(r0, sks + sk0 ', st), fits(r0, sks, st), r1 ≠ r2 ∨ sk ≠ sk0, r2 ≠ r1 ∨ sk0 ≠ sk ⊦ sks = [], (st[r2 -- sk0, val0][r1 -- sk, val]) = (st[r2 -- sk0, val0][(st[r2 -- sk0, val0][r -- sks1]) .refval -- sk, val]), is_referencevalue(st[r1 -- sk]), junkref(str, r1, st), junkref(str, r0, st), junkref(str, r, st), is_referencevalue(st[r0 -- (sks + sk0 ')]), is_referencevalue(st[r -- (sks1 + sk ')]), is_referencevalue(val0), is_referencevalue(val)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : refkey, , inj-01, ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)])]]