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Proof step 19 from proof sharing-twopaths (previous step)

# sks1 = # refs0, st[r -- sks] = refval(r0), st[r -- sks0] = refval(refs0 .last), st[r0 -- sks1] = refval(refs0 .last), fits(r0, sks1, st), validrefs(str, r0 ' + refs0, mkclasstype(`java.lang.Object' .class), st), fits(r, sks, st), fits(r, sks0, st) ⊦ refs0 .last = jvmref, r0 = jvmref, sks0 = [], sks = [], sks = sks0, r = jvmref, refs0 = [], ∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2], sks ⊑ sks0

User applied rule exists right

And obtained the following new goals

Proof step 18:
# sks1 = # refs0, st[r -- sks] = refval(r0), st[r -- sks0] = refval(refs0 .last), st[r0 -- sks1] = refval(refs0 .last), fits(r0, sks1, st), validrefs(str, r0 ' + refs0, mkclasstype(`java.lang.Object' .class), st), fits(r, sks, st), fits(r, sks0, st) ⊦ refs0 .last = jvmref, r0 = jvmref, sks0 = [], sks = [], sks = sks0, r = jvmref, refs0 = [], fits(r, sks + sks1, st) ∧ fits(r, sks0, st) ∧ sks + sks1 ≠ sks0 ∧ sks + sks1 ≠ [] ∧ sks0 ≠ [] ∧ st[r -- (sks + sks1)] .refval ≠ jvmref ∧ st[r -- (sks + sks1)] = st[r -- sks0], sks ⊑ sks0

Rule argument

[EXRARG : pos: right 8, [extquanttermlist: (sks + sks1, sks0) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sks + sks1, sks0)]]