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Proof step 32 from proof sharing-twopaths (previous step)

refs0 .last = st[r -- sks0] .refval, fits(r, sks0, st), fits(r, sks, st), validrefs(str, st[r -- sks] .refval ' + refs0, mkclasstype(`java.lang.Object' .class), st) ⊦ refs0 = [], r = jvmref, sks = sks0, sks = [], sks0 = [], st[r -- sks] .refval = jvmref, refs0 .last = jvmref, sks ⊑ sks0, hasSharing(r, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 31:
st[r -- sks0] = refval(r0) ∧ is_referencevalue(st[r -- sks0]), refs0 .last = r0, fits(r, sks0, st), fits(r, sks, st), validrefs(str, st[r -- sks] .refval ' + refs0, mkclasstype(`java.lang.Object' .class), st) ⊦ refs0 = [], r = jvmref, sks = sks0, sks = [], sks0 = [], st[r -- sks] .refval = jvmref, refs0 .last = jvmref, sks ⊑ sks0, hasSharing(r, st)

Rule argument

[speclemmaarg: is_referencevalue(val) ,r = val .refval ↔ val = refval(r) ,[val, r] → [st[r -- sks0], r0] ,T ,javavalue , ,elim-refval ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ is_referencevalue(val) → val .refval = jvmref], [CSIMPELIM : is_referencevalue(val) ⊦ r = val .refval ↔ val = refval(r)])], [EXTRATERMS : (st[r -- sks0], r0)]]