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Proof step 36 from proof sharing-twopaths (previous step)

refs .first = st[r -- sks] .refval, refs .last = st[r -- sks0] .refval, fits(r, sks0, st), fits(r, sks, st), validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st) ⊦ sks = [], sks0 = [], refs .first = jvmref, refs .last = jvmref, r = jvmref, sks = sks0, refs = [], sks ⊑ sks0, hasSharing(r, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 35:
refs = r0 + refs0, r0 = st[r -- sks] .refval, refs .last = st[r -- sks0] .refval, fits(r, sks0, st), fits(r, sks, st), validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st) ⊦ sks = [], sks0 = [], r0 = jvmref, refs .last = jvmref, r = jvmref, sks = sks0, refs = [], sks ⊑ sks0, hasSharing(r, st)

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [refs, r0, refs0] ,T ,list-data ,references ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (refs, r0, refs0)]]