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Proof step 8 from proof sharing-twopaths (previous step)

st[r -- sks] .refval = st[r -- sks0] .refval, validrefs(str, st[r -- sks0] .refval ', mkclasstype(`java.lang.Object' .class), st), fits(r, sks, st), fits(r, sks0, st) ⊦ st[r -- sks0] .refval = jvmref, sks0 = [], sks = [], sks = sks0, r = jvmref, hasSharing(r, st), sks ⊑ sks0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ hasSharing(r, st) ↔ (∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2])
Proof step 7:
st[r -- sks] .refval = st[r -- sks0] .refval, validrefs(str, st[r -- sks0] .refval ', mkclasstype(`java.lang.Object' .class), st), fits(r, sks, st), fits(r, sks0, st) ⊦ st[r -- sks0] .refval = jvmref, sks0 = [], sks = [], sks = sks0, r = jvmref, ∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2], sks ⊑ sks0

Rule argument

[crewrite-arg: hasSharing-def, F, [st, r] → [st, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]