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Proof step 12 from proof at=get-offset (previous step)

i→n(i1) < # getarray(r, i0, i, st), 0 ≤ i1, 0 ≤ i1 + i0, i1 ≤ i, 0 ≤ i0, 0 ≤ i, 0 ≤ i + i0, 0 < i, ∀ r, st, i1, i0, j0. i→n(j0) < i→n(i + 1) → (0 ≤ i0 ∧ 0 < j0 + i0 ∧ 0 < j0 ∧ i1 < j0 ∧ 0 ≤ i1 + i0 ∧ 0 ≤ i1 → st[r -- (i1 + i0) '] = (getarray(r, i0, j0, st)[i→n(i1)])) ⊦ st[r -- (i1 + i0) '] = (getarray(r, i0, i, st)[i→n(i1)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ 0 < j → # getarray(r, i, j, st) = i→n(j)
Proof step 11:
0 ≤ i1, 0 ≤ i1 + i0, i1 ≤ i, 0 ≤ i0, 0 ≤ i, 0 ≤ i + i0, 0 < i, i1 < i, ∀ r, st, i1, i0, j0. i→n(j0) < i→n(i + 1) → (0 ≤ i0 ∧ 0 < j0 + i0 ∧ 0 < j0 ∧ i1 < j0 ∧ 0 ≤ i1 + i0 ∧ 0 ≤ i1 → st[r -- (i1 + i0) '] = (getarray(r, i0, j0, st)[i→n(i1)])) ⊦ st[r -- (i1 + i0) '] = (getarray(r, i0, i, st)[i→n(i1)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 < j → abs(j) = j], [CSIMPSEQ : ⊦ 0 ≤ i → abs(i) = i], [CSIMPSEQ : ⊦ i→n(i) < i→n(j) ↔ abs(i) < abs(j)])]]