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Proof step 15 from proof at=get-offset (previous step)

0 ≤ i1, 0 ≤ i1 + i0, i1 < j, 0 < j + i0, 0 ≤ i0, 1 < j, 0 < j, ∀ r, st, i1, i0, j0. i→n(j0) < i→n(j) → (0 ≤ i0 ∧ 0 < j0 + i0 ∧ 0 < j0 ∧ i1 < j0 ∧ 0 ≤ i1 + i0 ∧ 0 ≤ i1 → st[r -- (i1 + i0) '] = (getarray(r, i0, j0, st)[i→n(i1)])) ⊦ st[r -- (i1 + i0) '] = (getarray(r, i0, j - 1, st) + st[r -- (i0 + j - 1) '] ')[i→n(i1)]

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 14:
j = i + 1, 0 ≤ i1, 0 ≤ i1 + i0, i1 < j, 0 < j + i0, 0 ≤ i0, 1 < j, 0 < j, ∀ r, st, i1, i0, j0. i→n(j0) < i→n(j) → (0 ≤ i0 ∧ 0 < j0 + i0 ∧ 0 < j0 ∧ i1 < j0 ∧ 0 ≤ i1 + i0 ∧ 0 ≤ i1 → st[r -- (i1 + i0) '] = (getarray(r, i0, j0, st)[i→n(i1)])) ⊦ st[r -- (i1 + i0) '] = (getarray(r, i0, i, st) + st[r -- (i0 + j - 1) '] ')[i→n(i1)]

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [j, 1, i] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (j, 1, i)]]