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Proof step 21 from proof at=get-offset (previous step)

i < j + i0, i0 ≤ i, 0 ≤ i, 0 ≤ i0, 0 < j + i0, 0 < j ⊦ st[r -- i '] = (getarray(r, i0, j, st)[i→n(i - i0)])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 20:
i = i1 + i0, i < j + i0, i0 ≤ i, 0 ≤ i, 0 ≤ i0, 0 < j + i0, 0 < j ⊦ st[r -- i '] = (getarray(r, i0, j, st)[i→n(i1)])

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [i, i0, i1] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (i, i0, i1)]]