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Proof step 13 from proof at=get (previous step)

j = i0 + 1, i < j, 0 ≤ i, 1 < j, 0 < j, ∀ r, st, i, j0. i→n(j0) < i→n(j) → (true → (0 ≤ i ∧ i < j0 → st[r -- i '] = (getarray(r, 0, j0, st)[i→n(i)]))) ⊦ st[r -- i '] = (getarray(r, 0, i0, st) + st[r -- i0 '] ')[i→n(i)]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i ≤ i0, 0 ≤ i, 0 ≤ i0, 0 < i0, ∀ r, st, i, j0. i→n(j0) < i→n(i0 + 1) → (true → (0 ≤ i ∧ i < j0 → st[r -- i '] = (getarray(r, 0, j0, st)[i→n(i)]))) ⊦ st[r -- i '] = (getarray(r, 0, i0, st) + st[r -- i0 '] ')[i→n(i)]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ 0 < i ∧ 0 < j → 0 < i + j], [CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i < j + 1 ↔ i ≤ j])]]