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Proof step 17 from proof at=get (conclusion)

⊦ 0 ≤ i ∧ i < j → st[r -- i '] = (getarray(r, 0, j, st)[i→n(i)])

User applied rule induction

And obtained the following new goals

Proof step 16:
true, ∀ r, st, i, j0. i→n(j0) < i→n(j) → (true → (0 ≤ i ∧ i < j0 → st[r -- i '] = (getarray(r, 0, j0, st)[i→n(i)]))) ⊦ 0 ≤ i ∧ i < j → st[r -- i '] = (getarray(r, 0, j, st)[i→n(i)])

Rule argument

[INDHYPARG : [STANDARDINDUCTIONTYPE : ], true, false, i→n(j), [] → [], <]

Additional information

[[CONCRETESIMPRULES : ([CSIMPLESSPRED : <])], [EXTRATERMS : (i→n(j))]]