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Proof step 4 from proof bar-firstn (previous step)

n→i(n) ≤ j ⊦ firstn(n, getbytearray(r, i, j, st)) = getbytearray(r, i, n→i(n), st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ firstn(n, bytes) = sublist(0, n, bytes)
Proof step 3:
n→i(n) ≤ j ⊦ sublist(0, n, getbytearray(r, i, j, st)) = getbytearray(r, i, n→i(n), st)

Rule argument

[speclemmaarg: ,firstn(n, bytes) = sublist(0, n, bytes) ,[bytes, n] → [getbytearray(r, i, j, st), n] ,F ,list-del ,bytelist ,first-sub ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (getbytearray(r, i, j, st), n)]]