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Proof step 3 from proof bar-len-02 (conclusion)

⊦ 0 ≤ j → # getbytearray(r, i, j, st) = i→n(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ getbytearray(r, i, j, st) = bytevalues(getarray(r, i, j, st))
Proof step 2:
⊦ 0 ≤ j → # getarray(r, i, j, st) = i→n(j)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i→n(i) = i→n(j) ↔ abs(i) = abs(j)], [CSIMPSEQ : ⊦ # bytevalues(vals) = # vals])]]