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Proof step 12 from proof bar-neq (previous step)

bytevalues(getarray(r, i, j, st)) + bytevalues(getarray(r, i + j, j0 - j, st)) = bytevalues(getarray(r0, i0, j0, st0)), j ≤ j0, 0 ≤ j, 0 ≤ j0 ⊦ bytevalues(getarray(r, i, j, st)) = bytevalues(getarray(r0, i0, j, st0))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
j0 = i1 + j, bytevalues(getarray(r, i, j, st)) + bytevalues(getarray(r, i + j, i1, st)) = bytevalues(getarray(r0, i0, j0, st0)), j ≤ j0, 0 ≤ j, 0 ≤ j0 ⊦ bytevalues(getarray(r, i, j, st)) = bytevalues(getarray(r0, i0, j, st0))

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [j0, j, i1] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (j0, j, i1)]]