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Proof step 7 from proof bar-restn (previous step)

∀ j, i, r, st. n→i(m) ≤ j ∧ 0 ≤ i → restn(m, getbytearray(r, i, j, st)) = getbytearray(r, i + n→i(m), j - n→i(m), st) ⊦ n→i(m +1) ≤ j ∧ 0 ≤ i → restn(m +1, getbytearray(r, i, j, st)) = getbytearray(r, i + n→i(m +1), j - n→i(m +1), st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ getbytearray(r, i, j, st) = bytevalues(getarray(r, i, j, st))
Proof step 6:
n→i(m) < j, 0 ≤ i, 0 < j, ∀ j0, i0, r0, st0. ¬ j0 < n→i(m) ∧ ¬ i0 < 0 → restn(m, bytevalues(getarray(r0, i0, j0, st0))) = bytevalues(getarray(r0, i0 + n→i(m), j0 - n→i(m), st0)) ⊦ restn(m, bytevalues(getarray(r, i, j, st)) .rest) = bytevalues(getarray(r, (n→i(m) + 1) + i, j - n→i(m) + 1, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ n→i(m) < j → 0 < j], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + 1 ≤ j ↔ i < j], [CSIMPSEQ : ⊦ n→i(m + n) = n→i(m) + n→i(n)], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ restn(n + 1, bytes) = restn(n, bytes .rest)], [CSIMPSEQ : ⊦ m +1 = m + 1])]]