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Proof step 26 from proof bar-sublist (conclusion)

⊦ n→i(m) + n→i(n) ≤ j → sublist(m, n, getbytearray(r, i, j, st)) = getbytearray(r, i + n→i(m), n→i(n), st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
n→i(m) + n→i(n) ≤ j ⊦ sublist(m, n, getbytearray(r, i, j, st)) = getbytearray(r, i + n→i(m), n→i(n), st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]