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Proof step 4 from proof comp-next (previous step)

i0 ≤ i, 0 ≤ i, 0 ≤ i0, ∀ i0. ¬ i0 < 0 ∧ ¬ i ≤ i0 → st0[r1 -- (i1 + i0) '] = st0[r2 -- (i2 + i0) '] ⊦ r1 = r2, st0[r1 -- (i1 + i0) '] = ((i0 = i ⊃ st0[r1 -- (i1 + i) ']; st0[r2 -- (i2 + i0) ']))

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 3:
i0 ≠ i, i0 ≤ i, 0 ≤ i, 0 ≤ i0, ∀ i0. ¬ i0 < 0 ∧ ¬ i ≤ i0 → st0[r1 -- (i1 + i0) '] = st0[r2 -- (i2 + i0) '] ⊦ st0[r1 -- (i1 + i0) '] = st0[r2 -- (i2 + i0) '], r1 = r2

Rule argument

[CASEDARG : pos: right 2, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i])]]