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Proof step 1 from proof comp-same (previous step)

0 < i4, 0 < j0, 0 < i3, 0 ≤ j, j0 ≤ 1 + i4, 0 < i1, 0 ≤ i2, j0 ≤ i4, i + i4 * (i1 - i2) < i3, i2 < i1, j < i3, 0 ≤ i, 0 ≤ i4, ∀ j. ¬ j < 0 ∧ ¬ i3 ≤ j → st[r -- (i1 + j) '] = st[r -- (i2 + j) '], ∀ j, i2, i1, i, i4, i3, st, r. i→n(j) < i→n(j0) → ( i2 < i1 ∧ i + i4 * (i1 - i2) < i3 ∧ 0 ≤ i2 ∧ 0 ≤ i4 ∧ 0 ≤ j ∧ j ≤ i4 ∧ 0 ≤ i ∧ (∀ j. 0 ≤ j ∧ j < i3 → st[r -- (i1 + j) '] = st[r -- (i2 + j) ']) → st[r -- (i1 + i + j * (i1 - i2)) '] = st[r -- (i1 + i) ']) ⊦ 0 = j0, st[r -- (i1 + j) '] = st[r -- (i2 + j) '], st[r -- (i1 + i + j0 * (i1 - i2)) '] = st[r -- (i1 + i) ']

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 14, [QUANTTERMLIST : (j)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)], [CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (j)]]