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Proof step 5 from proof copy-at (previous step)

true, ∀ j0, r1, r0, r, i, i0, st, sk. i→n(j0) < i→n(j) → (true → (r1 ≠ r0 → (arraycopy(r, i, r0, i0, j0, st)[r1 -- sk]) = st[r1 -- sk])) ⊦ r1 ≠ r0 → (arraycopy(r, i, r0, i0, j, st)[r1 -- sk]) = st[r1 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ j0, r1, r0, r, i, i0, st, sk. i→n(j0) < i→n(j) → (true → (r1 ≠ r0 → (arraycopy(r, i, r0, i0, j0, st)[r1 -- sk]) = st[r1 -- sk])) ⊦ r1 = r0, (arraycopy(r, i, r0, i0, j, st)[r1 -- sk]) = st[r1 -- sk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]