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Proof step 10 from proof copy-between (previous step)

true, ∀ j1, r, r0, i0, j0, i, st. i→n(j1) < i→n(j) → (true → (r ≠ r0 ∧ i0 ≤ j0 ∧ j0 < i0 + j1 → (arraycopy(r, i, r0, i0, j1, st)[r0 -- j0 ']) = st[r -- ((j0 - i0) + i) '])) ⊦ r ≠ r0 ∧ i0 ≤ j0 ∧ j0 < i0 + j → (arraycopy(r, i, r0, i0, j, st)[r0 -- j0 ']) = st[r -- ((j0 - i0) + i) ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
j0 < i0 + j, i0 ≤ j0, 0 < j, ∀ j1, r, r0, i0, j0, i, st. i→n(j1) < i→n(j) → (true → (r ≠ r0 ∧ i0 ≤ j0 ∧ j0 < i0 + j1 → (arraycopy(r, i, r0, i0, j1, st)[r0 -- j0 ']) = st[r -- ((j0 - i0) + i) '])) ⊦ (arraycopy(r, i, r0, i0, j, st)[r0 -- j0 ']) = st[r -- (i + j0 - i0) '], r = r0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ i < i + j ↔ 0 < j], [CSIMPFORWARD : ⊦ i ≤ j ∧ j < j0 → i < j0], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + (j - i0) = i + j - i0])]]