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Proof step 11 from proof copy-in-lower (previous step)

true, ∀ j1, j0, i0, r0, r, i, st. i→n(j1) < i→n(j) → (true → (j0 < i0 → (r0 -- j0 ' ∈ arraycopy(r, i, r0, i0, j1, st) ↔ r0 -- j0 ' ∈ st))) ⊦ j0 < i0 → (r0 -- j0 ' ∈ arraycopy(r, i, r0, i0, j, st) ↔ r0 -- j0 ' ∈ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
j0 < i0, ∀ j1, j0, i0, r0, r, i, st. i→n(j1) < i→n(j) → (true → (j0 < i0 → (r0 -- j0 ' ∈ arraycopy(r, i, r0, i0, j1, st) ↔ r0 -- j0 ' ∈ st))) ⊦ r0 -- j0 ' ∈ arraycopy(r, i, r0, i0, j, st) ↔ r0 -- j0 ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]