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Proof step 5 from proof copy-in-upper (previous step)

true, ∀ j1, i0, j0, r0, r, i, st. i→n(j1) < i→n(j) → (true → (i0 + j1 ≤ j0 → (r0 -- j0 ' ∈ arraycopy(r, i, r0, i0, j1, st) ↔ r0 -- j0 ' ∈ st))) ⊦ i0 + j ≤ j0 → (r0 -- j0 ' ∈ arraycopy(r, i, r0, i0, j, st) ↔ r0 -- j0 ' ∈ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i0 + j ≤ j0, ∀ j1, i0, j0, r0, r, i, st. i→n(j1) < i→n(j) → (true → (i0 + j1 ≤ j0 → (r0 -- j0 ' ∈ arraycopy(r, i, r0, i0, j1, st) ↔ r0 -- j0 ' ∈ st))) ⊦ r0 -- j0 ' ∈ arraycopy(r, i, r0, i0, j, st) ↔ r0 -- j0 ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]