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Proof step 6 from proof copy-in (previous step)

true, ∀ j0, r1, i, r, i1, r0, i0, st. i→n(j0) < i→n(j) → (true → (r1 -- i ' ∈ arraycopy(r, i1, r0, i0, j0, st) ↔ r1 -- i ' ∈ st) ∨ r1 = r0) ⊦ (r1 -- i ' ∈ arraycopy(r, i1, r0, i0, j, st) ↔ r1 -- i ' ∈ st) ∨ r1 = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ j0, r1, i, r, i1, r0, i0, st. i→n(j0) < i→n(j) → (true → (r1 -- i ' ∈ arraycopy(r, i1, r0, i0, j0, st) ↔ r1 -- i ' ∈ st) ∨ r1 = r0) ⊦ r1 = r0, r1 -- i ' ∈ arraycopy(r, i1, r0, i0, j, st) ↔ r1 -- i ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]