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Proof step 5 from proof get-alleq (previous step)

∀ j. j ≤ 0 ∧ 0 ≤ j → st[r -- (i + j) '] = st0[r0 -- (i0 + j) '], ∀ j0, r, i, st, r0, i0, st0. i→n(j0) < i→n(1) → (true → (getarray(r, i, j0, st) = getarray(r0, i0, j0, st0) ↔ (∀ j1. 0 ≤ j1 ∧ j1 < j0 → st[r -- (i + j1) '] = st0[r0 -- (i0 + j1) ']))) ⊦ st[r -- i '] = st0[r0 -- i0 ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ j. ¬ 0 < j ∧ ¬ j < 0 → st[r -- (i + j) '] = st0[r0 -- (i0 + j) '], ∀ j0, r, i, st, r0, i0, st0. i→n(j0) < i→n(1) → (true → (getarray(r, i, j0, st) = getarray(r0, i0, j0, st0) ↔ (∀ j1. 0 ≤ j1 ∧ j1 < j0 → st[r -- (i + j1) '] = st0[r0 -- (i0 + j1) ']))) ⊦ st[r -- i '] = st0[r0 -- i0 ']

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i])]]