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Proof step 10 from proof get-del-01 (previous step)

1 < j, 0 < j, ∀ j0, r, r0, i, st. i→n(j0) < i→n(j) → (true → r = r0 ∨ getarray(r, i, j0, st -- r0) = getarray(r, i, j0, st)) ⊦ getarray(r, i, j - 1, st -- r0) + (st -- r0)[r -- (i + j - 1) '] = getarray(r, i, j, st), r = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
1 < j, 0 < j, ∀ j0, r, r0, i, st. i→n(j0) < i→n(j) → (true → r = r0 ∨ getarray(r, i, j0, st -- r0) = getarray(r, i, j0, st)) ⊦ r = r0, getarray(r, i, j - 1, st -- r0) + st[r -- (i + j - 1) '] ' = getarray(r, i, j, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j], [CSIMPSEQ : ⊦ vals + val = vals + val '], [CSIMPSEQ : ⊦ r ≠ r0 → (st -- r)[r0 -- sk0] = st[r0 -- sk0]])]]