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Proof step 2 from proof get-eqex-02 (conclusion)

r ≠ r0 ⊦ getarray(r, i, j, st0) = vals ∧ eqex(st, st0, r0) → getarray(r, i, j, st) = vals

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
r ≠ r0 ⊦ getarray(r, i, j, st0) ≠ vals ∧ eqex(st, st0, r0) → getarray(r, i, j, st) ≠ vals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ eqex(st, st0, r) → eqex(st0, st, r)])]]