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Proof step 6 from proof get-eqex-03 (previous step)

j0 < j, eqex(st, st0, r0), eqex(st0, st, r0), 0 ≤ j0, 0 < j ⊦ st0[r -- (i + j0) '] = st[r -- (i + j0) '], r = r0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ eqex(st, st0, r) ↔ st -- r = st0 -- r
Proof step 5:
j0 < j, st -- r0 = st0 -- r0, eqex(st0, st, r0), 0 ≤ j0, 0 < j ⊦ st0[r -- (i + j0) '] = st[r -- (i + j0) '], r = r0

Rule argument

[speclemmaarg: ,eqex(st, st0, r) ↔ st -- r = st0 -- r ,[r, st0, st] → [r0, st0, st] ,F ,storefunsx , ,eqex ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r0, st0, st)]]