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Proof step 11 from proof get-first (previous step)

1 < j, 0 < j, ∀ j0, r, i, st. i→n(j0) < i→n(j) → (0 < j0 → getarray(r, i, j0, st) .first = st[r -- i ']) ⊦ (getarray(r, i, j - 1, st) + st[r -- (i + j - 1) ']) .first = st[r -- i ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
1 < j, 0 < j, ∀ j0, r, i, st. i→n(j0) < i→n(j) → (0 < j0 → getarray(r, i, j0, st) .first = st[r -- i ']) ⊦ (getarray(r, i, j - 1, st) + st[r -- (i + j - 1) '] ') .first = st[r -- i ']

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ vals + val = vals + val '])]]