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Proof step 11 from proof get-get (previous step)

n < # getarray(r, i, i0, st), 0 < i0, n→i(n) ≤ i0, ∀ j0, n, r, i, st. i→n(j0) < i→n(i0 + 1) → (n→i(n) < j0 → (getarray(r, i, j0, st)[n]) = st[r -- (i + n→i(n)) ']) ⊦ (getarray(r, i, i0, st)[n]) = st[r -- (i + n→i(n)) '], n = i→n(i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ 0 < j → # getarray(r, i, j, st) = i→n(j)
Proof step 10:
n < i→n(i0), n→i(n) ≤ i0, 0 < i0, ∀ j0, n, r, i, st. i→n(j0) < i→n(i0 + 1) → (n→i(n) < j0 → (getarray(r, i, j0, st)[n]) = st[r -- (i + n→i(n)) ']) ⊦ n = i→n(i0), (getarray(r, i, i0, st)[n]) = st[r -- (i + n→i(n)) '], i0 = 0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i→n(i) = 0 ↔ i = 0], [CSIMPFORWARD : ⊦ m < n → n ≠ 0])]]