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Proof step 15 from proof get-get (previous step)

n = # getarray(r, i, i0, st), 0 < i0, n→i(n) ≤ i0, ∀ j0, n, r, i, st. i→n(j0) < i→n(i0 + 1) → (n→i(n) < j0 → (getarray(r, i, j0, st)[n]) = st[r -- (i + n→i(n)) ']) ⊦ st[r -- (i + i0) '] = st[r -- (i + n→i(n)) ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
⊦ 0 < j → # getarray(r, i, j, st) = i→n(j)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 < i → n→i(i→n(i)) = i], [CSIMPSEQ : ⊦ i + j = j + i])]]