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Proof step 17 from proof get-get (previous step)

j = i0 + 1, 1 < j, n→i(n) < j, ∀ j0, n, r, i, st. i→n(j0) < i→n(j) → (n→i(n) < j0 → (getarray(r, i, j0, st)[n]) = st[r -- (i + n→i(n)) ']) ⊦ (getarray(r, i, i0, st) + st[r -- (i + j - 1) '] ')[n] = st[r -- (i + n→i(n)) ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
0 < i0, n→i(n) ≤ i0, ∀ j0, n, r, i, st. i→n(j0) < i→n(i0 + 1) → (n→i(n) < j0 → (getarray(r, i, j0, st)[n]) = st[r -- (i + n→i(n)) ']) ⊦ (getarray(r, i, i0, st) + st[r -- (i + i0) '] ')[n] = st[r -- (i + n→i(n)) ']

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 1 ≤ i ↔ 0 < i], [CSIMPSEQ : ⊦ i < j + 1 ↔ i ≤ j], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j - i = j])]]